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x^2+6x+9=(16)(x-3)
We move all terms to the left:
x^2+6x+9-((16)(x-3))=0
We calculate terms in parentheses: -(16(x-3)), so:We get rid of parentheses
16(x-3)
We multiply parentheses
16x-48
Back to the equation:
-(16x-48)
x^2+6x-16x+48+9=0
We add all the numbers together, and all the variables
x^2-10x+57=0
a = 1; b = -10; c = +57;
Δ = b2-4ac
Δ = -102-4·1·57
Δ = -128
Delta is less than zero, so there is no solution for the equation
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